How do you write $log_x(64)=3$ in exponential form?

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Answer 1 · 2018-05-09T12:37:49

$x^3=64$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)log_b x=nhArrx=b^n$

$"here "x=64,b=x" and "n=3$

$rArrlog_x 64=3rArrx^3=64$

Answer 2 · 2018-05-09T13:12:13

$64=4^3$

$log_x (64) = 3$

$log_x (4^3 )=3$

$3log_x 4 = 3 -> x=4$

Hence, we can express the identity in exponential form as: $64=4^3$

How do you write log_x(64)=3log_x(64)=3 in exponential form?