How do you write #log_a(a)=1# in exponential form?
1 Answer
Apr 30, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#"here "b=a,n=1" and "x=a#
#rArra=a^1larrcolor(blue)"in exponential form"#
