How do you write $log_7 49=2$ in exponential form?

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Answer 1 · 2016-09-28T09:47:57

And so $log_(7)49=2$ can be rewritten as $7^2=49$

The exponential form:

$a^b=c$ - which says "a multiplied by itself b times equals c"

can be rewritten as:

$log_(a)c=b$ - which says "a is multiplied by itself to arrive at c b-number of times"

And so $log_(7)49=2$ can be rewritten as $7^2=49$

How do you write log_7 49=2log_7 49=2 in exponential form?