How do you write #log_7 49=2# in exponential form?

1 Answer
MathFact-orials.blogspot.com
Sep 28, 2016

And so #log_(7)49=2# can be rewritten as #7^2=49#

Explanation:

The exponential form:

#a^b=c# - which says "a multiplied by itself b times equals c"

can be rewritten as:

#log_(a)c=b# - which says "a is multiplied by itself to arrive at c b-number of times"

And so #log_(7)49=2# can be rewritten as #7^2=49#

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