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How do you write #log_.25 16=-4# in exponential form?

1 Answer

Jul 10, 2018

# (0.25)^-4=16 #

Explanation:

#log_a m= x# then , # a^x =m#

#log_.25 16 = -4 or log_(1/4) 16 = -4# or

#16= (1/4)^-4 or 16 = 1/(1/4)^4 :. 16 = 16#

# (0.25)^-4=16 # [Ans]

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