How do you write $log_.25 16=-4$ in exponential form?

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Answer 1 · 2018-07-10T12:33:26

$(0.25)^-4=16$

$log_a m= x$ then , $a^x =m$

$log_.25 16 = -4 or log_(1/4) 16 = -4$ or

$16= (1/4)^-4 or 16 = 1/(1/4)^4 :. 16 = 16$

$(0.25)^-4=16$ [Ans]

How do you write log_.25 16=-4log_.25 16=-4 in exponential form?