How do you write #log_243 3 =1/5# in exponential form?

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How do you write #log_243 3 =1/5# in exponential form?

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Answer 1 · 2016-08-10T11:44:54

I found: #3=243^(1/5)#

Explanation:

You can use the definition of log where the base of the log #243# becomes the base of the exponential with #1/5# as exponent; you get:
#log_(243)3=1/5#
#3=243^(1/5)#

or: #3=243^(1/5)=root5(243)#

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How do you write #log_243 3 =1/5# in exponential form?

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