How do you write ${log}_{\frac{1}{4}} 64 = - 3$ $log_(1/4) 64 = -3$ in exponential form?

Question

How do you write ${log}_{\frac{1}{4}} 64 = - 3$ $log_(1/4) 64 = -3$ in exponential form?

1 Answer

Impact of this question

2976 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-15T02:56:55

Try this:

Explanation:

Use the definition of log:
${log}_{a} b = x \to a^{x} = b$ $log_ab=x ->a^x=b$
in your case:
$64 = {(\frac{1}{4})}^{- 3}$ $64=(1/4)^-3$
or:
$64 = 4^{3}$ $64=4^3$

Science

Math

Humanities

... and beyond

How do you write ${log}_{\frac{1}{4}} 64 = - 3$ $log_(1/4) 64 = -3$ in exponential form?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write log1464=−3log_(1/4) 64 = -3 in exponential form?

1 Answer

Explanation:

Related questions

Impact of this question

How do you write ${log}_{\frac{1}{4}} 64 = - 3$ $log_(1/4) 64 = -3$ in exponential form?