How do you write $log_(1/25)5=-1/2$ in exponential form?

Question

How do you write $log_(1/25)5=-1/2$ in exponential form?

2 Answers

Impact of this question

4429 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-21T15:13:01

$(1/25)^(-1/2)=5$

Explanation:

$log_ab=x$ in exponential form is written as $a^x=b$

Hence $log_(1/25)5=-1/2$ can be written in exponential form as $(1/25)^(-1/2)=5$

Answer 2 · 2018-03-21T15:17:32

$5=(1/25)^(-1/2)$

Explanation:

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)log_b x=nhArrx=b^n$

$"here "x=5,b=1/25" and "n=-1/2$

$rArrlog_(1/25)5=-1/2hArr5=(1/25)^(-1/2)$

Science

Math

Humanities

... and beyond

How do you write $log_(1/25)5=-1/2$ in exponential form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write log_(1/25)5=-1/2log_(1/25)5=-1/2 in exponential form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you write $log_(1/25)5=-1/2$ in exponential form?