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How do you write #e^(1/2)=1.6487# in logarithmic form?

1 Answer

Oct 30, 2017

# e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.#

Explanation:

Recall that, #e^x=y iff lny=x.#

#:. e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.#

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