How do you write conversion factors that correspond to the following concentration: 0.15% (v/v) acetic acid?
1 Answer
Here's how you can do that.
Explanation:
A
In this case, your solution will contain
0.15%"v/v" = "0.15 mL acetic acid"/"100 mL solution"
To use this as a conversion factor, rearrange keeping in mind that
- what is given by the probme goes on the bottom, i.e. as the denomiantor
- what must be calcualted goes on top, i.e. as the numerator
So, let's say that you want to find the amount of solute present in
"0.15 mL acetic acid"/"100 mL solution" color(white)(color(black)(larr)/color(black)(larr)) "what is needed goes on top"/"what is given goes on the bottom"
You will have
250 color(red)(cancel(color(black)("mL solution"))) * "0.15 mL acetic acid"/(100color(red)(cancel(color(black)("mL solution")))) = "0.38 mL acetic acid"
Now let's say that you want to figure out what volume of solution will contain
"100 mL solution"/"0.15 mL acetic acid" color(white)(color(black)(larr)/color(black)(larr)) "what is needed goes on top"/"what is given goes on the bottom"
You will have
0.035 color(red)(cancel(color(black)("mL acetic acid"))) * "100 mL solution"/(0.15 color(red)(cancel(color(black)("mL acetic acid")))) = "23 mL solution"