How do you write an inequality and solve given "two thirds of a number added to six is at least twenty two"?

Question

6478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-13T21:44:12

#x >= 24#

#"two-thirds of a number " rarr 2/3x#

#"added to " 6" " rarr 6+2/3x#

'Is at least' #22# means it can be equal to #22#, or more than #22#.

#6+2/3x >= 22#

#2/3x >= 22-6#

#2/3x >= 16#

#3/2 xx2/3x >= 3/2xx16#

#x >= 24#