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How do you write an equation of a line perpendicular to y=3+2x, passing through (4, -1)?

1 Answer

May 9, 2017

#x+2y=2#

Explanation:

Given line is y = 2x + 3. Its slope = 2

Let m be the slope of required line .
Then #mxx2 = - 1#. So, m = - 1/2

Let the required equation be #y = - 1/2 x +c #

Since it passes through (4,-1), we get
#- 1 = - 1/2xx4 +c or c = 1#

Hence the equation is #y = - 1/2 x+1#

#rArr x+2y = 2#

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