How do you write an equation of a line passing through (5, 0), perpendicular to #4x + y = -1#?

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Answer 1 · 2016-09-14T14:55:34

#x-4y-5=0#.

A Useful Result : The Eqn. of the line passing through #(x_0,y_0)#

and #bot# to line# : ax+by+c=0# is #b(x-x_0)=a(y-y_0)#.

Using this Result, we can immediately write the reqd. eqn. of line as,

#1(x-5)=4(y-0), i.e., x-4y-5=0#

Alternatively, rewriting the given eqn. as # : y=-4x-1#, we get

the slope of this line is #-4#.

Therefore, the slope of the reqd. #bot# line must be #1/4#, which,

passes through a pt. #(5,0)#.

By the Slope-Point Form, the reqd. eqn. is,

#y-0=1/4(x-5), or, x-4y-5=0#, as we had it earlier!.

Enjoy Maths.!