How do you write an equation of a line passing through (4, -3), perpendicular to #y=-4x+3#?

1 Answer
Jim G.
Mar 17, 2018

#y=1/4x-4#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#y=-4x+3" is in this form"#

#"with slope m "=-4#

#"Given a line with slope m then the slope of a line"#
#"perpendicular to it is "#

#•color(white)(x)m_(color(red)"perpendicular")=-1/m#

#rArrm_("perpendicular")=-1/(-4)=1/4#

#rArry=1/4x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(4,-3)" into the partial equation"#

#-3=1+brArrb=-3-1=-4#

#rArry=1/4x-4larrcolor(red)"perpendicular line"#

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