How do you write an equation of a line going through #2^x-5<64#?

1 Answer
Alan P.
Dec 20, 2016

As expressed this question does not make any sense.

Explanation:

#2^x-5 < 64# is not a point.

It could be solved for #x# as
#color(white)("XXX")2^x-5 < 64#

#color(white)("XXX")rarr 2^x < 69#

#color(white)("XXX")rarr log_2 2^x < log_2 69#

#color(white)("XXX")rarr x < log_2 69#

then using a calculator evaluating #log_2 69 ~~6.108524457#

In the Cartesian plane this is a region composed of all points to the left of #x = 6.108524457# (approx.)

I suppose you could argue that the equation #x=0# (for example) is the equation of a line going through (i.e. completely contained in) this region.

Related questions
See all questions in Logarithmic Models
Impact of this question
1034 views around the world
You can reuse this answer
Creative Commons License