How do you write an equation of a line going through #2^x-5<64#?

1 Answer
Dec 20, 2016

As expressed this question does not make any sense.

Explanation:

#2^x-5 < 64# is not a point.

It could be solved for #x# as
#color(white)("XXX")2^x-5 < 64#

#color(white)("XXX")rarr 2^x < 69#

#color(white)("XXX")rarr log_2 2^x < log_2 69#

#color(white)("XXX")rarr x < log_2 69#

then using a calculator evaluating #log_2 69 ~~6.108524457#

In the Cartesian plane this is a region composed of all points to the left of #x = 6.108524457# (approx.)

I suppose you could argue that the equation #x=0# (for example) is the equation of a line going through (i.e. completely contained in) this region.