How do you write an equation of a line given (5, -2) parallel to line #3y+7x=-8#?

1 Answer
John D.
Jul 7, 2017

#3y + 7x = 29#

Explanation:

Here's a quick trick: parallel lines in standard form will always have the same coefficients in front of the #x# and #y#. So what we can do is write this equation:

#3y + 7x = ?#

This equation represents every possible line that is parallel to #3y + 7x = -8#, and the value put in place of the question mark determines the placement of that line on the graph. So, to find the equation of the parallel line passing through #(5, -2)#, all we need to do is plug #(5, -2)# into our equation and solve it.

#y = -2#
#x = 5#

#3y + 7x = ?#

#3(-2) + 7(5) = ?#

#-6 + 35 = ?#

#29 = ?#

So we need to replace our #?# with #29#.

#3y + 7x = 29#

Final Answer

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