How do you write an equation in slope intercept form given that the line passes through the point (-2, -5) and has a slope of -3?

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How do you write an equation in slope intercept form given that the line passes through the point (-2, -5) and has a slope of -3?

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Answer 1 · 2015-05-30T08:12:20

The main formula of a line is;
#y=ax+b#

We should use one point to find the real equation. If we use (-2,-5) point;
#y= ax+b => -5=-2a+b#;
a is the slope of the equation, we found that as #-3#;
#-5=(-2*-3) + b => -5=6 +b => b=-11#;
So the equation of the line will be;
#y=ax+b => ul (y= -3x-11)#

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How do you write an equation in slope intercept form given that the line passes through the point (-2, -5) and has a slope of -3?

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