How do you write an equation for the line perpendicular to $y = 2 x - 5$ $y=2x-5$ that contains (-9,6)?

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How do you write an equation for the line perpendicular to $y = 2 x - 5$ $y=2x-5$ that contains (-9,6)?

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Answer 1 · 2015-05-19T17:52:55

The perpendicular would have its slope= $- \frac{1}{2}$ $-1/2$ . Since it contains (-9,6), its equation would be y-6= $- \frac{1}{2} (x + 9)$ $-1/2 (x+9)$ .

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How do you write an equation for the line perpendicular to $y = 2 x - 5$ $y=2x-5$ that contains (-9,6)?

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How do you write an equation for the line perpendicular to y=2x−5y=2x-5 that contains (-9,6)?

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How do you write an equation for the line perpendicular to $y = 2 x - 5$ $y=2x-5$ that contains (-9,6)?