How do you write a rule for the nth term of the geometric sequence and then find a_5a5 given a_3=-144, r=0.5a3=144,r=0.5?

1 Answer
Dec 15, 2017

a_n=-576(0.5)^(n-1),a_5=-36an=576(0.5)n1,a5=36

Explanation:

"the nth term of a geometric sequence is "the nth term of a geometric sequence is

•color(white)(x)a_n=ar^(n-1)xan=arn1

"where a is the first term and r the common ratio"where a is the first term and r the common ratio

a_3=ar^2=-144a3=ar2=144

rArra=-144/(0.25)=-576larrcolor(blue)"first term"a=1440.25=576first term

rArra_n=-576(0.5)^(n-1)an=576(0.5)n1

rArra_5=-576xx(0.5)^4=-36a5=576×(0.5)4=36