How do you write a quadratic function in intercept form who has x intercepts -2, 5/4 and passes through points (9/4, -51/32)?
1 Answer
May 31, 2017
Explanation:
#"the equation of a quadratic in "color(blue)"intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-b)(x-c))color(white)(2/2)|)))#
where a is a constant and b, c the x-intercepts.
#rArry=a(x+2)(x-5/4)#
#"to find a, substitute " (9/4,-51/32)" into the equation"#
#-51/32=axx17/4xx1#
#rArra=-51/32xx4/17=-3/8#
#rArry=-3/8(x+2)(x-5/4)larrcolor(red)" in intercept form"#
graph{-3/8(x+2)(x-5/4) [-10, 10, -5, 5]}
