How do you write a polar equation for the circle centered at the origin with radius #sqrt2#?

1 Answer
Jim G.
Jan 11, 2017

#r^2=2#

Explanation:

The equation of a circle centred at the origin is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(x^2+y^2=r^2)color(white)(2/2)|)))#
where r is the radius.

#x^2+y^2=(sqrt2)^2#

#rArrx^2+y^2=2larr" equation in cartesian form"#

To convert from #color(blue)" cartesian to polar form"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(r=sqrt(x^2+y^2))color(white)(2/2)|)))#

#rArrx^2+y^2=2tor^2=2larr" in polar form"#

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