How do you write $a^2 = 36$ in log form?

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Answer 1 · 2016-05-09T11:44:42

In this form, $a=+-6$ . The logarithmic form is $log_a 36 = 2$ and, solving this, a = 6..

If $x=b^y$ , the inverse relation is $y=log_b x$ .

Here, x = 36, b = a and y = 2.

So, $log_a 36=log_a(6^2)=2 log_a 6=2$ .

Now, $log_a 6 =1$ . So, a = 6, as $log_a a=1$ ..

How do you write a^2 = 36a^2 = 36 in log form?