How do you write #3x-4y-10=0# in polar form?

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Answer 1 · 2017-11-06T17:33:26

#r=10/(3costheta-4sintheta)#

we have the conversion eqns

#r^2=x^2+y^2--(1)#

#x=rcostheta--(2)#

#y=rsintheta---(3)#

we have

#3x-4y-10=0#

using #(2)" & "(3)#

#3rcostheta-4rsintheta-10=0#

#r(3costheta-4sintheta)=10#

#r=10/(3costheta-4sintheta)#