How do you write #3x - 2y= 5 # into slope intercept form?

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Answer 1 · 2015-08-22T19:22:43

#y = 3/2x - 5/2#

For a general line #y#, the equation of the line in slope-intercept form looks like this

#color(blue)(y = mx + b)" "#, where

#m# - the slope of the line;
#b# - the #y#-intercept.

So basically, all you have to do to write the equation for your line in sloper-intercept form is isolate #y# on one side of the equation.

Start by adding #-3x# to both sides to get

#-color(red)(cancel(color(black)(3x))) + color(red)(cancel(color(black)(3x))) - 2y = 5 - 3x#

#-2y = -3x + 5#

Now divide both sides of the equation by #-2# to get

#(color(red)(cancel(color(black)(-2))) * y)/color(red)(cancel(color(black)(-2))) = ((-3))/((-2))x + 5/((-2))#

#color(green)(y = 3/2x - 5/2)#