How do you write #3x(10-4x)-6(x=5)+15# in standard form?

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Answer 1 · 2017-10-24T01:42:44

#-4x^2 + 8x - 15 = 0#

#ax^2 + bx + c = 9#is the standard form of quadratic equation.

Removing braces,

#30x -12x^2 -6x = 30 + 15#

#-12x^2 + 24x = 45#

#-12x^2 + 24x -45 = 0 #

# dividing both sides by 3,

#-4x2 + 8x -15 = 0#