How do you write 32=x5 in Logarithm form?

2 Answers
Aug 28, 2016

32=x55=logx32.

Aug 28, 2016

It can be written:

logx32=5 or log32x=15

Explanation:

Given:

32=x5

If we take logs base x we find:

logx32=logxx5=5

Alternatively, if we take logs base 32 we find:

1=log3232=log32x5=5log32x

Hence:

log32x=15