How do you write 32=x5 in Logarithm form?
2 Answers
Aug 28, 2016
Aug 28, 2016
It can be written:
logx32=5 orlog32x=15
Explanation:
Given:
32=x5
If we take logs base
logx32=logxx5=5
Alternatively, if we take logs base
1=log3232=log32x5=5log32x
Hence:
log32x=15