How do you write #2x^2+4x-5# into vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. May 13, 2015 #(-b/2a) = -4/4 = -1# #f(-b/2a) = f(-1) = 2 - 4 - 5 = -7# Factored form: #f(x) = 2(x + 1)^2 - 7# Check: Develop #f(x) = 2(x^2 + 2x + 1) -5 = 2x^2 + 4x - 5#. Correct Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1348 views around the world You can reuse this answer Creative Commons License