How do you write $2(x-5)^2 + 8$ in standard form?

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Answer 1 · 2015-05-05T12:58:25

Standard form for a quadratic is
$ax^2+bx+c=0$

$2(x-5)^2+8$

$=2(x^2-10x+25)+8$

$=2x^2-20x+58$ is in standard notation

How do you write 2(x-5)^2 + 82(x-5)^2 + 8 in standard form?