How do you write $(1/4)^-6=4096$ in log form?

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Answer 1 · 2016-06-15T04:52:56

$log_(1/4)4096=-6$

As $a^b=c$ can be written as $log_ac=b$

$(1/4)^(-6)=4096$ can be written as

$log_(1/4)4096=-6$

How do you write (1/4)^-6=4096(1/4)^-6=4096 in log form?