How do you write $(1/3)^-5 = 243$ in log form?

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Answer 1 · 2018-03-29T04:38:46

$log_{1/3}243 = -5$

$"base"^{"exponent"} = "answer"\ \ leftrightarrow\ \ log_{"base"}"answer"="exponent"$

How do you write (1/3)^-5 = 243(1/3)^-5 = 243 in log form?