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How do you verify that the x values #pi/6, (5pi)/6# are solutions to #csc^4x-4csc^2x=0#?

1 Answer

Shwetank Mauria

Feb 19, 2017

By putting #x=pi/6# and #x=(5pi)/6# in #csc^4x-4csc^2x=0#

Explanation:

If #x=pi/6#, we have #cscx=2#

Therefore #csc^4x-4csc^2x=2^4-4xx2^2=16-16=0#

Similarly if #x=(5pi)/6# #cscx=2#

and again #csc^4x-4csc^2x=2^4-4xx2^2=16-16=0#

Hence #x=pi/6# and #x=(5pi)/6# are solutions to #csc^4x-4csc^2x=0#

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