How do you verify that the x values $pi/12, (5pi)/12$ are solutions to $3tan^2 2x-1=0$ ?

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How do you verify that the x values $pi/12, (5pi)/12$ are solutions to $3tan^2 2x-1=0$ ?

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Answer 1 · 2017-02-27T05:00:00

Use Trig table of special arcs -->
$x = pi/12 --> 2x = pi/6 --> tan (pi/6) = sqrt3/3 --> tan^2 (pi/6) = 3/9 --> 3tan^2 2x - 1 = 9/9 - 1 = 0$ . Proved!

$x = (5pi)/12 --> 2x = (5pi)/6 --> tan ((5pi)/6) = -sqrt3/3 -->tan^2 ((5pi)/6) = 3/9 --> 3 tan^2 (2x) - 1 = 9/9 - 1 = 0$ . Proved

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How do you verify that the x values $pi/12, (5pi)/12$ are solutions to $3tan^2 2x-1=0$ ?

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How do you verify that the x values pi/12, (5pi)/12pi/12, (5pi)/12 are solutions to 3tan^2 2x-1=03tan^2 2x-1=0?

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How do you verify that the x values $pi/12, (5pi)/12$ are solutions to $3tan^2 2x-1=0$ ?