How do you verify (1+tanx)/(sinx)=cscx+secx?

1 Answer
Jul 28, 2015

Use the following rules :
tanx=sinx/cosx
1/sinx=cscx
1/cosx=secx

Explanation:

Start from the Left hand side("LHS") :

=>"LHS"=(1+tanx)/sinx=1/sinx+tanx/sinx
=cscx+tanx xx1/sinx=cscx+cancel(sinx)/cosx xx1/cancel(sinx)=cscx+1/cosx=color(blue)(cscx+secx)

QED