How do you use the quadratic formula to solve #x^2-2x+2=0#?
1 Answer
Aug 16, 2016
This quadratic has zeros
Explanation:
#x^2-2x+2=0#
This is in the form
It has zeros given by the quadratic formula:
#x = (-b+-sqrt(b^2-4ac))/(2a)#
#=(2+-sqrt((-2)^2-4(1)(2)))/(2*1)#
#=(2+-sqrt(4-8))/2#
#=(2+-sqrt(-4))/2#
#=(2+-(sqrt(4))i)/2#
#=(2+-2i)/2#
#=1+-i#
