How do I use the quadratic formula to solve $4x^2+x-1=0$ ?

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Answer 1 · 2014-09-30T03:46:55

$ax^2+bx+c=0$

$4x^2+1x-1=0$

$a=4, b=1, c=-1$

Quadratic formula

$x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(-(1)+-sqrt((1)^2-4(4)(-1)))/(2(4))$

$x=(-1+-sqrt(1+16))/8$

$x=(-1+-sqrt(17))/8$

How do I use the quadratic formula to solve 4x^2+x-1=04x^2+x-1=0?