How do you use the quadratic formula to find both solutions to the quadratic equation $5 - 10 x - 3 x^{2} = 0$ $5 - 10x - 3x^2 = 0$ ?

Question

1609 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-28T23:29:50

Solve $y = - 3 x^{2} - 10 x + 5 = 0$ $y = -3x^2 - 10x + 5 = 0$

$D = d^{2} = b^{2} - 4 a c = 100 + 60 = 160 \to d = \pm 4 \sqrt{10}$ $D = d^2 = b^2 - 4ac = 100 + 60 = 160 -> d = +- 4sqrt10$

$x = - \frac{5}{3} \pm \frac{4 \sqrt{10}}{6} = \frac{5}{3} \pm \frac{2 \sqrt{10}}{3}$ $x = - 5/3 +- (4sqrt10)/6 = 5/3 +- (2sqrt10)/ 3$

How do you use the quadratic formula to find both solutions to the quadratic equation 5−10x−3x2=05 - 10x - 3x^2 = 0?