How do you use the limit definition to find the slope of the tangent line to the graph # f(x) = x^2#? Calculus Derivatives Tangent Line to a Curve 1 Answer Steve M Oct 21, 2016 # f'(x) = 2x # Explanation: By definition # f'(x) = d/dxf(x) = lim_{h->0) (f(x+h)-f(x))/h # So if # f(x)=x^2# then: # f'(x) = lim_{h->0) ((x+h)^2-x^2)/h # # :. f'(x) = lim_{h->0) (x^2+2hx+h^2-x^2)/h # # :. f'(x) = lim_{h->0) ( 2hx+h^2 )/h # # :. f'(x) = lim_{h->0) ( 2x+h ) # # :. f'(x) = 2x # Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1305 views around the world You can reuse this answer Creative Commons License