How do you use the intermediate value theorem to explain why #f(x)=1/16x^4-x^3+3# has a zero in the interval [1,2]?
1 Answer
Nov 3, 2016
The function is continuous and
Explanation:
The function
Therefore we calculate
and
Therefore as
As one value is above zero and the other below zero
graph{x^4/16-x^3+3 [-5.94, 6.55, -3.34, 2.9]}
