How do you use the important points to sketch the graph of #y = -1/3x²#?

1 Answer
Mar 25, 2017

graph{-(1/3)x^2 [-27.59, 27.98, -15.53, 12.27]}
for tracing any graph you should scrounge some points.

Explanation:

1) put some simple values of x and obtain y like, here, at x=0, y=0
at x= #+-1#, y= -#1/3#
at x#rarr +-infty#, y#rarr -infty#
2) check for maxima and minima of function using derivative.
3) also put some simple points like at x=#+-1,+-3,# and find y
4) interchange x and y, if no change appears it means the #f(x)# is symmetrical about line x=y
With little practice I hope you will be able to trace curves.