How do you use the important points to sketch the graph of #3x^2-8#?

1 Answer
Oct 6, 2017

We have:

# y = 3x^2-8 #

Let us examine some of the properties of this function:

  • This is a polynomial (linear combination of powers of #x# alone). The highest power of #x# is #2#, so it is a polynomial of degree #2#, or a quadratic function.

  • The function is quadratic, so will have a #uu# shape or an #nn# . The coefficient of #x# is #3#, which is positive, so it will have a #uu# shape.

  • If we look at #f(x)=0# then #3x^2=8 => x^2 = 8/3# leading to two roots, #x=+-sqrt(8/3)#

  • If we replace #x# by #-x# then we have

    # f(-x) = 3(-x)^2 -8 = 3(x)^2 -8 = f(x) #
    So, we deduce that #f(x)# is an even function, and symmetrical about #Oy#

  • If we put #x=0# then we get:

    # x=0 => f(0) = -8 #

Which gives us enough information to sketch the graph, which here is done using the inbuild Socratic graphing functionality:

graph{3x^2-8 [-5, 5, -10, 5]}