How do you use the geometric mean to find the 7th term in a geometric sequence if the 6th term is 12 and the 8th term?

1 Answer
Mar 23, 2016

If the common ratio is positive, then:

a_7 = sqrt(a_6 * a_8)

Explanation:

If you are given the 6th and 8th terms of a geometric series then there are two possibilities for the 7th term, namely +-sqrt(a_6 * a_8)

If you are told that the common ratio is positive or that all of the terms of the sequence are positive then a_7 = sqrt(a_6 * a_8) is the geometric mean of a_6 and a_8. Otherwise it could be -sqrt(a_6 * a_8).

Why does this work?

The general term of a geometric sequence can be written:

a_n = a r^(n-1)

where a is the initial term and r the common ratio.

If a, r > 0 then:

sqrt(a_6 * a_8) = sqrt(ar^5 * a r^7) = sqrt(ar^6 * ar^6) = ar^6 = a_7

In fact, in general:

sqrt(a_n * a_(n+2)) = a_(n+1)

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In the given example a_6 = 12 and let us suppose a_8 = 48

Then a_7 = sqrt(a_6 * a_8) = sqrt(12 * 48) = sqrt(24*24) = 24