How do you use the distributive property to simplify #(y+2)10#?
1 Answer
May 10, 2017
Explanation:
#"that is " a(b+c)=(b+c)a=ab+ac#
#rArr(y+2)color(red)(10)#
#=(yxxcolor(red)(10))+(2xxcolor(red)(10))#
#=10y+20#
