How do you use the Distributive Property to rewrite each expression $- 6 a (2 b + 5 c)$ $-6a(2b+5c)$ ?

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Answer 1 · 2016-12-06T16:16:16

$- 12 a b - 30 a c$ $-12ab - 30ac$

For this problem you "distribute" the term $- 6 a$ $-6a$ across each term in the parenthesis:

$- 6 a (2 b + 5 c) \to (- 6 a) (2 b) + (- 6 a) (5 c) \to$ $-6a(2b + 5c) -> (-6a)(2b) + (-6a)(5c) ->$

$(- 6 \cdot 2 a b) + (- 6 \cdot 5 a c) \to - 12 a b + - 30 a c \to$ $(-6*2ab) + (-6*5ac) -> -12ab + -30ac ->$

$- 12 a b - 30 a c$ $-12ab - 30ac$

How do you use the Distributive Property to rewrite each expression -6a(2b+5c)−6a(2b+5c)-6a(2b+5c)?