How do you use the discriminant to determine the nature of the solutions given $y = x^2 + 25– 10x$ ?

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Answer 1 · 2016-07-02T15:40:54

The roots are real and identical because, discriminant $D=0$
The roots are $x_1=5/2$ and $x_2=5/2$

The given equation is

$y=x^2-10x+25$

and $a=1$ and $b=-10$ and $c=25$

The discriminant

$D=sqrt(b^2-4ac)$

$D=sqrt((-10)^2-4(1)(25))$

$D=sqrt(100-100)$

$D=0$

God bless....I hope the explanation is useful.

How do you use the discriminant to determine the nature of the solutions given y = x^2 + 25– 10xy = x^2 + 25– 10x?