How do you use the discriminant to determine the nature of the solutions given $–4p^2 – 1.8p + 0.2 = 0$ ?

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Answer 1 · 2017-01-14T14:28:12

The solutions are $={-0.54,0.09}$

We compare this equation to

$ax^2+bx+c=0$

$-4p^2-1.8p+0.2=0$

The discriminant is

$Delta=b^2-4ac=(-1.8)^2-4*(-4)*(0.2)$

$=3.24+3.2=6.44$

As $Delta >0$ , we have 2 real roots

$p_1=(1.8+sqrt6.44)/(2*-4)=(1.8+2.54)/-8=-0.54$

$p_2=(1.8-sqrt6.44)/(2*-4)=(1.8-2.54)/-8=0.09$

How do you use the discriminant to determine the nature of the solutions given –4p^2 – 1.8p + 0.2 = 0 –4p^2 – 1.8p + 0.2 = 0?