How do you use the discriminant to determine the nature of the solutions given $2x^2+4x+2$ ?

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Answer 1 · 2018-04-06T14:15:42

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Discriminant is given by $sqrt(b^2-4ac)$

The equation $2x^2+4x+2$ is in the general form $ax^2+bx+c$

So the discriminant is

$sqrt(4^2-4times2times2)$

= $sqrt0$

= $0$

From your discriminant, you can tell it has one real double root ie at that point, it bounces off in the shape of a parabola

How do you use the discriminant to determine the nature of the solutions given 2x^2+4x+2 2x^2+4x+2?