How do you use synthetic substitution to evaluate f(-2) for f(x)=x^4-4x^3-4x+6f(x)=x44x34x+6?

1 Answer
Dec 16, 2015

(see below for method of evaluation)
f(-2)=62f(2)=62

Explanation:

Evaluation of f(x)=color(blue)(1)x^4color(blue)(-4)x^3color(blue)(+0)x^2color(blue)(-4)xcolor(blue)(+6)f(x)=1x44x3+0x24x+6
for f(color(red)(-2))f(2)
Notice the expansion of the expression to include the implied coefficients of color(blue)(1)1 for x^4x4 and of color(blue)(0)0 for x^2x2

Initial set-up:
{: (,"|",color(blue)(1),color(blue)(-4),color(blue)(+0),color(blue)(-4),color(blue)(+6),color(white)("XXXXXXXX")"line [1]"), (,"|",,,,,,color(white)("XXXXXXXX")"line[2]"), ("----",,"----","----","----","----","----",), (xxcolor(red)((-2)),"|",color(green)(1),,,,,color(white)("XXXXXXXX")"line [3]") :}

For each column

  • Multiply the last number written on line [3] by color(red)((-2)) and write the product on line [2] of the next column
  • Add the numbers in lines [1] and [2] of the next column and write the sum in line [3] of that column.

The number written in the last column of line [3] will be the value of f(color(red)(-2))

{: (,"|",color(blue)(1),color(blue)(-4),color(blue)(+0),color(blue)(-4),color(blue)(+6),color(white)("XXXXXXXX")"line [1]"), (,"|",,-2,12,-24,56,color(white)("XXXXXXXX")"line[2]"), ("-----------",,"----","----","----","----","----",), (xxcolor(red)((-2)),"|",color(green)(1),-6,12,-28,color(cyan)(62),color(white)("XXXXXXXX")"line [3]") :}