How do you use synthetic division to divide 4x^3 + 7x^2 – 13x – 3 by x + 3?

1 Answer
Jul 30, 2015

color(red)((4x^3+7x^2-13x-3)/(x+3) = 4x^2-5x+2-9/(x+3))

Explanation:

Step 1. Write only the coefficients of x in the dividend inside an upside-down division symbol.

|4" "color(white)(1)7color(white)(1)-13" " "-3
|color(white)(1)
stackrel("——————————————)

Step 2. Put the divisor at the left.

color(red)(-3)|4" "color(white)(1)7color(white)(1)-13" " "-3
" "color(white)(1)|
" "color(white)(1)stackrel("——————————————)

Step 3. Drop the first coefficient of the dividend below the division symbol.

-3|4" "color(white)(1)7color(white)(1)-13" " "-3
" "color(white)(1)|
" "color(white)(1)stackrel("——————————————)
" "color(white)(1)|color(red)(4)

Step 4. Multiply the result by the constant, and put the product in the next column.

-3|4" "color(white)(1)7color(white)(1)-13" " "-3
" "color(white)(1)|color(white)(1)color(red)(-12)
" "color(white)(1)stackrel("——————————————)
" "color(white)(1)|4

Step 5. Add down the column.

-3|4" "color(white)(1)7color(white)(1)-13" " "-3
" "color(white)(1)|-12
" "color(white)(1)stackrel("——————————————)
" "color(white)(1)|4color(white)(1)color(red)(-5)

Step 6. Repeat Steps 4 and 5 until you can go no farther.

-3|4" "color(white)(1)7color(white)(1)-13" " "-3
" "color(white)(1)|-12" "color(white)(1)15" "color(white)(1)-6
" "stackrel("——————————————)
color(blue)(" "color(white)(1)|4-5" "" "2)" "color(white)(1)color(red)(-9)

(4x^3+7x^2-13x-3)/(x+3) = 4x^2-5x+2-9/(x+3)

Check:

(x+3)(4x^2-5x+2-9/(x+3)) = (x+3)(4x^2-5x+2)-9

= 4x^3-5x^2+2x+12x^2-15x+6-9 = 4x^3+7x^2-13x-3