How do you use quadratic formula to solve $x^{2} - 5 = 0$ $x^2-5=0$ ?

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Answer 1 · 2015-05-12T20:52:37

A quadratic equation is written in the form:
$a x^{2} + b x + c = 0$ $ax^2 + bx + c = 0$

The given equation $x^{2} - 5 = 0$ $x^2-5=0$ can be rewritten as $x^{2} + 0 x - 5 = 0$ $x^2+0x-5=0$

Where:
$a = 1$ $a=1$
$b = 0$ $b=0$
$c = - 5$ $c=-5$

The quadratic formula can be used to find the roots of any quadratic equation.

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x= (-b+- sqrt(b^2-4ac))/(2a)$

So I encourage you to plug in the values from this equation and simplify.

The answers should be $x = \pm \sqrt{5}$ $x = +-sqrt(5)$

How do you use quadratic formula to solve x2−5=0 x^2-5=0?