How do you use quadratic formula to solve 3x^2-8=0 ?

1 Answer
Gió
May 7, 2015

Consider your equation in the general form ax^2-bx+c=0
Where you have:
a=3
b=0
c=-8
Now you can apply the quadratic formula:
x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)
Try by yourself: you should get two results. If you do not get them look at the solution below:
.
.
.
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Solution:
x_1=sqrt(96)/6=1.633
x_2=-sqrt(96)/6=-1.633

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