How do you use quadratic formula to solve $2x^2 + 4x + 2 = 0$ ?

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Answer 1 · 2015-06-12T08:36:33

The solution for this equation is
$color(red)(x = -1$

$2x^2+4x+2$
The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=2, b=4, c=2$

The Discriminant is given by:
$Delta=b^2-4*a*c$
$= (4)^2-(4*2*2)$
$= 16 - 16=0$
As $Delta=0$ then there is only one solution.

The solution is found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

As $Delta = 0$ , $x = ((-4)+-sqrt(0))/(2*2) = -4/4 = -1$
So , $x = -1$

How do you use quadratic formula to solve 2x^2 + 4x + 2 = 02x^2 + 4x + 2 = 0?